**How to read 5-band resistor color code**

Carbon resistors are maximum, not unusualplace in digital equipment. They encompass a high-grade ceramic rod or cone ( known as the substrate that’s deposited a skinny resistive movie of carbon. The numerical fee in their resistance is indicated via way of means of a shadeation code which includes bands of various hues imprinted on the frame of the resistor. The shadeation used on this code and the digits represented via way of means of them are given withinside the desk below: Usually, the code includes 4 bands. Starting from left to proper.

**How to study five-band resistor shadeation code**

**The five band resistor shadeation bands are interpreted as follows:**

The first band suggests the primary digit **resistor color code** withinside the numerical fee of the resistance The 2nd band offers the second digit. The 1/3 band is a decimal multiplier i.e, it offers the number of zeroes after the primary digits. The fourth band offers resistance tolerance. Its shadeation is both silver and gold.

The silver band suggests a tolerance of ± 10 %, and the gold band indicates a tolerance of ±five %. If there’s no fourth band, tolerance is known to be ± 20%. By tolerance, the way the feasible version from the marketplace fee. For example, a thousand Ω resistor with a tolerance of ± 10 % may have a real resistance everywhere between 900 Ω and 1100 Ω.

**How to calculate the Five Band Resistor Color Code?**

Certain precision resistors with a tolerance of two %, 1 %, or much less are typically shadeation-coded with 5 bands as proven withinside the parent given below:

5 band color codeBegin on the band closest to 1 end. The first band is the primary digit of the resistance fee, the second band is the second one digit, the 1/3 band is the 1/3 digit, the fourth band is a multiplier ( quantity of zeroes after the 1/3 digit), and the 5th suggests the percentage tolerance5 band shadeation code resistor

A five-band shadeation code resistor has four shadeation bands on the left facet and one shadeation band on the proper facet. The four shadeation bands on the left facet are very near different and the fifth shadeation band on the proper facet is separated from the primary four bands with a little space. A five-band shadeation code resistor has four shadeation bands on the left facet and one shadeation band on the proper facet.

The four shadeation bands at the left facet are grouped collectively to symbolize the resistance fee of a resistor and the fifth shadeation band at the proper facet suggests the tolerance of the resistor. The 1st shadeation band suggests the first sizeable fee or 1st digit of the resistors fee.

The second shadeation band suggests the second sizeable fee or second digit of the resistor fee.

**The fifth shadeation band suggests the resistor’s tolerance.**

The 1st, second, and third shadeation bands collectively make up a three-digit quantity, and the 4th shadeation band or multiplier is expanded with this three-digit quantity to reap the resistance fee of the resistor.

**Example:**

If the colors on a five-band resistor are in this order: brown, inexperienced, crimson, blue, and violet (as proven in the parent). The **Printed circuit board in china** values of shadeation bands could be like this: Brown = 1, Green = five, Red = 2, blue = 106, Violet = 0.10%.

In the shadeation code desk, brown has a fee of one that’s the first digit, inexperienced has a fee of five that’s the second one digit and crimson has a

In the shadeation code desk, brown has a fee of one that’s the first digit, inexperienced has a fee of five that’s the second digit and crimson has a fee of two that’s the third digit. The first, 2nd and 1/3 shadeation bands collectively make up a 3-digit quantity of 152. The 4th shadeation band blue has a fee of 106.

This fee is expanded with the 3-digit quantity 152 I.e., 152 x 106 = 152MΩ. Violet specifies that the tolerance is 0.10%. Therefore, the resistor shadeation coded with brown-inexperienced-crimson-blue-violet might have a resistance of 152MΩ with a tolerance of ± 0.10%.